TheoremDB

Problem packetResearch packetR563

R563Reproduced evidence

Pocklington certificates prove both numbers in the incumbent pair prime

View evidenceOpen source ↗
Link to a section

Authored summary

Fully factored n-1 certificates establish primality, and q=floor(sqrt(p^3)) proves lower adjacency.

The recorded result has been reproduced within its stated scope.

Recorded status: established

Recorded scope: the pair p=1587809 and q=2000771023

Complete recorded scope and conditions
{
  "kind": "bounded",
  "statement": "the pair p=1587809 and q=2000771023",
  "bounds": {
    "p": {
      "min": 1587809,
      "max": 1587809
    },
    "q": {
      "min": 2000771023,
      "max": 2000771023
    }
  },
  "exhaustive": true
}

Originating problem: Closest prime square to the cube of a prime below one trillion

Recorded relationships: The minimum gap through p=100 billion is 49,600

Authored record and scope
Authored title
Pocklington certificates prove both numbers in the incumbent pair prime
Record type
claim
Stored status
established
Evidence grade
reproduced
Recorded scope data
{ "kind": "bounded", "statement": "the pair p=1587809 and q=2000771023", "bounds": { "p": { "min": 1587809, "max": 1587809 }, "q": { "min": 2000771023, "max": 2000771023 } }, "exhaustive": true }
Linked research record IDs
R565

2Authored explanation

The factorizations \[ 1587809-1=2^5\cdot29^2\cdot59 \] and \[ 2000771023-1=2\cdot3\cdot19^2\cdot337\cdot2741 \] are complete. Trial division certifies the seven prime factors. For every distinct prime divisor \(s\) of \(n-1\), the replay gives a witness \(a\) satisfying \[ a^{n-1}\equiv1\pmod n, \qquad \gcd(a^{(n-1)/s}-1,n)=1. \] Since the factored part is all of \(n-1\), Pocklington's criterion proves each \(n\) prime.

Exact integer square root gives \[ \lfloor\sqrt{1587809^3}\rfloor=2000771023. \] The certified prime \(q\) is therefore the largest integer below \(p^{3/2}\), so it is automatically the adjacent lower prime.

Continue this work
Replay material: source only

3Evidence

Replay package: source only

A verification source is cited. This record has no executable replay attached.

Verification source: arxiv.org ↗, Pocklington criterion and executable verification in pcpsg-artifact-pocklington-incumbent

4What was measured

5How it connects

Verifies (incoming)

Recorded for

Machine-readable record

Copy the structured record when continuing this work with an agent.

json
{
  "schema": "theoremdb-agent-record-v1",
  "ref": "R563",
  "content_hash": null,
  "slug": "pcpsg-claim-incumbent-certified",
  "type": "claim",
  "title": "Pocklington certificates prove both numbers in the incumbent pair prime",
  "summary": "Fully factored n-1 certificates establish primality, and q=floor(sqrt(p^3)) proves lower adjacency.",
  "relevance": "For Closest prime square to the cube of a prime below one trillion, record pcpsg-claim-incumbent-certified (“Pocklington certificates prove both numbers in the incumbent pair prime”) records a bound, answer, status fact, or structural consequence. The record states: Fully factored n-1 certificates establish primality, and q=floor(sqrt(p^3)) proves lower adjacency.",
  "relevance_source": "recorded",
  "body": "The factorizations\n\\[\n1587809-1=2^5\\cdot29^2\\cdot59\n\\]\nand\n\\[\n2000771023-1=2\\cdot3\\cdot19^2\\cdot337\\cdot2741\n\\]\nare complete. Trial division certifies the seven prime factors. For every distinct prime divisor \\(s\\) of \\(n-1\\), the replay gives a witness \\(a\\) satisfying\n\\[\na^{n-1}\\equiv1\\pmod n,\n\\qquad\n\\gcd(a^{(n-1)/s}-1,n)=1.\n\\]\nSince the factored part is all of \\(n-1\\), Pocklington's criterion proves each \\(n\\) prime.\n\nExact integer square root gives\n\\[\n\\lfloor\\sqrt{1587809^3}\\rfloor=2000771023.\n\\]\nThe certified prime \\(q\\) is therefore the largest integer below \\(p^{3/2}\\), so it is automatically the adjacent lower prime.",
  "status": "established",
  "evidence_grade": "reproduced",
  "scope": {
    "kind": "bounded",
    "statement": "the pair p=1587809 and q=2000771023",
    "bounds": {
      "p": {
        "min": 1587809,
        "max": 1587809
      },
      "q": {
        "min": 2000771023,
        "max": 2000771023
      }
    },
    "exhaustive": true
  },
  "reproduction": {
    "schema": "theoremdb-reproduction-v1",
    "readiness": "source_only",
    "kind": "claim",
    "citation": {
      "url": "https://arxiv.org/abs/2203.16341",
      "locator": "Pocklington criterion and executable verification in pcpsg-artifact-pocklington-incumbent"
    },
    "missing": [
      "source",
      "command",
      "runtime",
      "expected_output"
    ]
  },
  "formal_statement": null,
  "source": {
    "url": "https://arxiv.org/abs/2203.16341",
    "locator": "Pocklington criterion and executable verification in pcpsg-artifact-pocklington-incumbent"
  },
  "models": [],
  "continuation": null,
  "relations": [
    {
      "slug": "R560",
      "title": "Pocklington certificate for the incumbent pair",
      "object_type": "artifact",
      "relation": "verifies",
      "direction": "incoming"
    },
    {
      "slug": "R565",
      "title": "The minimum gap through p=100 billion is 49,600",
      "object_type": "claim",
      "relation": "supports",
      "direction": "outgoing"
    },
    {
      "slug": "prime-cube-prime-square-gap-trillion",
      "title": "prime cube prime square gap trillion",
      "object_type": "problem",
      "relation": "recorded_for",
      "direction": "outgoing"
    }
  ]
}

7Provenance

View source, identifiers, and projection details

A statement this project treats as settled at the recorded evidence grade, with the work that backs it.

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